366 would not guarantee it. That’s not how probability works. You cannot guarantee a shared birthday without selecting people. And not to mention, birthdays aren’t evenly distributed.
I misunderstood the scenario. For some reason I was thinking that if you randomly selected people and had a duplicate birthday that’s what you didn’t want.
366 would not guarantee it. That’s not how probability works. You cannot guarantee a shared birthday without selecting people. And not to mention, birthdays aren’t evenly distributed.
Once you have more people than days in a year it’s not about statistics anymore
366 people wouldnt guarantee no shared birthdays though. There could still be one leap year baby in that bunch. But what are the odds in that?
2.6 • 10^-158 , if anyone is curious.
That sad experiment where 366 people in a room all have the exact same birthday.
Statisticly unlikely, but definitely possible.
I misunderstood the scenario. For some reason I was thinking that if you randomly selected people and had a duplicate birthday that’s what you didn’t want.
i also interpreted this how you did. you are not alone, internet stranger
deleted by creator
Oops – I meant 367!