RmDebArc_5@piefed.zip to tumblr@lemmy.worldEnglish · 9 days agoWho ever could it be?piefedimages.s3.eu-central-003.backblazeb2.comimagemessage-square40fedilinkarrow-up1476arrow-down123
arrow-up1453arrow-down1imageWho ever could it be?piefedimages.s3.eu-central-003.backblazeb2.comRmDebArc_5@piefed.zip to tumblr@lemmy.worldEnglish · 9 days agomessage-square40fedilink
minus-squaretensorpudding@lemmy.worldlinkfedilinkarrow-up15arrow-down1·9 days agoIf each friend in a group of four had an independent and identical 25% chance of being gay, the probability that at least two of them are gay is about 26%, I like those odds.
minus-squareChloé 🥕@lemmy.blahaj.zonelinkfedilinkarrow-up3arrow-down1·9 days agoare you sure it’s 26%? i’m arriving at around 57%, but maybe there’s a flaw in my reasoning
minus-squaretensorpudding@lemmy.worldlinkfedilinkarrow-up6·edit-29 days agoIts possible I made an error, I used 1 minus the cdf of the binomial distribution with n = 4 and p = 0.25 evaluated at 1, calculated from https://binomialdistributioncalculator.com/binomial-cdf-calculator/
minus-squareChloé 🥕@lemmy.blahaj.zonelinkfedilinkarrow-up5·9 days agohuh. i did the same thing, but by hand… oh wait no i see my mistake. you’re right, it’s about 26%. my bad 😅
minus-squareM.int@lemmy.ziplinkfedilinkarrow-up4·9 days ago@[email protected] is correct: P(at least 2 gay) = 1 - P(0 gay) - P(exactly 1 gay) = 1 - 0.75^4 - 4×0.25×0.75^3 = 1 - 0.31640625 - 0.421875 = 0.26171875 ≈ 26%
If each friend in a group of four had an independent and identical 25% chance of being gay, the probability that at least two of them are gay is about 26%, I like those odds.
are you sure it’s 26%? i’m arriving at around 57%, but maybe there’s a flaw in my reasoning
Its possible I made an error, I used 1 minus the cdf of the binomial distribution with n = 4 and p = 0.25 evaluated at 1, calculated from https://binomialdistributioncalculator.com/binomial-cdf-calculator/
huh. i did the same thing, but by hand…
oh wait no i see my mistake. you’re right, it’s about 26%. my bad 😅
@[email protected] is correct: